SOLUTION: Billy made a trip to California and back. The trip there took four hours and the trip back took 5 hours. He averaged 5mph faster on the trip there than on the return trip. Let r re
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Question 1048766: Billy made a trip to California and back. The trip there took four hours and the trip back took 5 hours. He averaged 5mph faster on the trip there than on the return trip. Let r represent his average speed on the trip back. What was Billy's average speed on both trips?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Distance equals rate times time, so the distance on the faster part of the trip is equal to )
, and the distance on the slower part of the trip is equal to 
. Presumably, neither California nor the place Billy started moved during the trip so we can assume that these two distances are the same. Therefore:
)
Solve for 
and then calculate 
John
My calculator said it, I believe it, that settles it
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