SOLUTION: In February 2011, Trevor Bayne became the youngest winner of the Daytona 500, with a time of 03:59:24 for the 500-mi race. At one point, Bayne was 80 miles closer to the finish tha

Question 1048557: In February 2011, Trevor Bayne became the youngest winner of the Daytona 500, with a time of 03:59:24 for the 500-mi race. At one point, Bayne was 80 miles closer to the finish than to the start. How far had Bayne traveled at that point?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Amount traveled =x
distance from start is x, distance from the finish is 500-x
When he was 80 miles closer to the finish than the start, his distance from the start, x is 80 more than his distance to the finish, 500-x. We need to subtract 80 from x to make the two distances equal.
Therefore, x-80=500-x, to set them equal to each other.
2x=580 miles
x=290 miles
500-x=210 miles
He is 80 miles closer to the finish than to the start.
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