SOLUTION: paul traveled to lexington at 70 mph. on the way back he averages 55 mph. the way back was 86 miles longer and took 2.6 hours longer to drive. how long was the scenic route from Le

Question 1048246: paul traveled to lexington at 70 mph. on the way back he averages 55 mph. the way back was 86 miles longer and took 2.6 hours longer to drive. how long was the scenic route from Lexington?
Found 2 solutions by Alan3354, advanced_Learner:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
paul traveled to lexington at 70 mph. on the way back he averages 55 mph. the way back was 86 miles longer and took 2.6 hours longer to drive. how long was the scenic route from Lexington?
----------------
d = r*t
r = rate going = 70 mi/hr, d = distance going, t = time going
---
d = 70t
----
d + 86 = 55*(t + 2.6)
---
70t + 85 = 55t + 143
15t = 58
t = 58/15
================
scenic d = 55*(58/15 + 2.6)
= 11*58/3 + 143
=~ 355.67 miles
Answer by advanced_Learner(501) (Show Source): You can put this solution on YOUR website!
paul traveled to lexington at 70 mph. on the way back he averages 55 mph. the way back was 86 miles longer and took 2.6 hours longer to drive. how long was the scenic route from Lexington?
how long means? hours or distance? i will solve for both.
To lexington
speed 70
distance d
time t
back
speed 55
distance d +86
time= t+2.6h
=

Solved by pluggable solver: EXPLAIN simplification of an expression

Your Result:

YOUR ANSWER

This is an equation! Solutions: t=9.53333333333333.

Graphical form: Equation was fully solved.
Text form: 15t=143 simplifies to 0=0
Cartoon (animation) form:
For tutors: simplify_cartoon( 15t=143 )

If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Moved these terms to the left
It becomes .

Look at .
Solved linear equation equivalent to 15*t-143 =0
It becomes .
Result:
This is an equation! Solutions: t=9.53333333333333.

Universal Simplifier and Solver

Done!

t is
going back time is
the required
d=
d=
d=(55)(12.1333)
d=
d= is the required scenic distance from lexington..
check that
70*9.5333 is
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