SOLUTION: a car leaves at 7am on a long trip travelling at 44 kph a second car leaves at 11am traveling 108 kph what time does the second car catch the first

Question 1047089: a car leaves at 7am on a long trip travelling at 44 kph a second car leaves at 11am traveling 108 kph what time does the second car catch the first
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39632) (Show Source): You can put this solution on YOUR website!
Use time quantities now and adjust to time points later.
11 AM from 7 AM is 3 hour difference.

SPEED TIME DISTANCE EARLY CAR 44 t+3 d LATER CAR 108 t d

Travel Rates Rule for constant travel rate, RT=D, relating rate, time, and distance.

Answer by MathTherapy(10559) (Show Source): You can put this solution on YOUR website!

a car leaves at 7am on a long trip travelling at 44 kph a second car leaves at 11am traveling 108 kph what time does the second car catch the first

Let time 2nd (faster) car takes to get to meetup point, be T
Then time 1st (slower) car takes to get to meetup point = T + 4
We then get the following DISTANCE equation: 108T = 44(T + 4)
108T = 44T + 176
108T - 44T = 176
64T = 176
T, or time 2nd (faster) car takes to get to meetup point = =
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