SOLUTION: Due to inclement weather, the pilot of the plane slows down the plane's regular flying rate by 25%. This results an additional 1.5hours in covering 3000km distance to its regular t

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Question 1045468: Due to inclement weather, the pilot of the plane slows down the plane's regular flying rate by 25%. This results an additional 1.5hours in covering 3000km distance to its regular time required for the trip. Find the regular rate of the trip
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39628)   (Show Source): You can put this solution on YOUR website!
r, regular rate --- unknown quantity for this example
f, fraction of regular rate  (assumed using either regular fraction OR decimalized)
t, regular time expected ----- unknown also in this example
h, amount of more time than regular
d, distance for the trip


Conditions             RATE       TIME      DISTANCE
REGULAR WEATHER         r           t        d
INCLEMENT WTHR          (1-f)r     t+h       d


This is a typical type of travel rates example. Form the two equations and solve for t and r.


Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!
Due to inclement weather, the pilot of the plane slows down the plane's regular flying rate by 25%. This results an additional 1.5hours in covering 3000km distance to its regular time required for the trip. Find the regular rate of the trip
Let regular rate be S

Then reduced rate during trip = .75S

Time to cover 3,000 km at regular rate: 

Time to cover 3,000 km at reduced rate: 

We then get the following TIME equation: 

3,000(.75) = 3,000 – 1.5(.75S) -------- Multiplying by LCD, .75S

2,250 = 3,000 – 1.125S

1.125S = 3,000 – 2,250

1.125S = 750

S, or regular rate =  = 

It is that SIMPLE, with just ONE (1) variable: the one you're looking for! 

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