SOLUTION: Mr. Fisher travels from Boise, Idaho, toward Casper, Wyoming, at a rate of 56 mi/hr. Mr. Collins leaves Casper for Boise at the same time, traveling at 64 mi/hr. If the cities are

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Question 1044865: Mr. Fisher travels from Boise, Idaho, toward Casper, Wyoming, at a rate of 56 mi/hr. Mr. Collins leaves Casper for Boise at the same time, traveling at 64 mi/hr. If the cities are 658 mi apart, how long will it be before the two men meet?
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39800) About Me  (Show Source):
You can put this solution on YOUR website!
               RATE      TIME      DISTANCE
Mr. Fisher       56       t         56t
Mr. Collins      64       t         64t
TOTAL                               658

56t%2B64t=658

Answer by ikleyn(53765) About Me  (Show Source):
You can put this solution on YOUR website!
.
Mr. Fisher travels from Boise, Idaho, toward Casper, Wyoming, at a rate of 56 mi/hr. Mr. Collins leaves Casper for Boise
at the same time, traveling at 64 mi/hr. If the cities are 658 mi apart, how long will it be before the two men meet?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

  "How long" = 658%2F%2856+%2B+64%29 = 658%2F120 hours.


Bad numbers? - Really bad.


The two cars move toward each other with the relative speed 56 + 64 = 120 miles per hour or 2 miles per minute. Hence


  "How long" = 658%2F2 minutes = 329 minutes = 5 hours and 29 minutes.

Much better.


Answer by MathTherapy(10810) About Me  (Show Source):
You can put this solution on YOUR website!

Mr. Fisher travels from Boise, Idaho, toward Casper, Wyoming, at a rate of 56 mi/hr. Mr. Collins leaves Casper for Boise at the same time, traveling at 64 mi/hr. If the cities are 658 mi apart, how long will it be before the two men meet?
Let time to meet be T
Then we get the following DISTANCE equation: 56T + 64T = 658
120T = 658
T, or time taken to meet = 658%2F120, or