Since 5C3 is only 10, we will just list them all, add them and count the number of different sums of weights: 1. 1+2+3 = 6 2. 1+2+4 = 7 3. 1+2+5 = 8 4. 1+3+4 = 8 5. 1+3+5 = 8 6. 1+4+5 = 10 7. 2+3+4 = 9 9. 2+3+5 = 10 9. 2+4+5 = 11 10. 3+4+5 = 12 So there are 7 different sums of weights, {6,7,8,9,10,11,12} Edwin