RATE TIME DISTANCE AS DONE r t d IF FASTER r+k t-h d
Let speed of car be S
Then hypothetical speed = S + 15
We then get the following TIME equation:_____
450(2)(S + 15) = 450(2S) + 3S(S + 15) --------- Multiplying by LCD, 2S(S + 15)
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Factor the trinomial on the left to solve for S: the speed of the car. You should get