SOLUTION: (i) a car leaves town A at 09 50 and travels towards town B at an average speed of 44km/h. at what time will it reach town which is 66km away? (ii) on reaching town B, it con

Question 1042417: (i) a car leaves town A at 09 50 and travels towards town B at an average speed of 44km/h. at what time will it reach town which is 66km away? (ii) on reaching town B, it continues its journey towards town c but reduces its speed by 7km/h. it reaches town C at 13 20. find the distance between town B and town C. (iii) calculate the average speed for the whole journey, between town A and town C

Answer by chen.aavaz(62) (Show Source): You can put this solution on YOUR website!
Time needed for the car to travel from A to B:
t=S/V where S is the distance between the two towns and V the car speed.
Therefore t=66/44 = 1.5h, so it reaches B 1.5 hour after 9:50, that is, 11:20.
The reduced speed after it reaches B is .
The car reaches town C at 13:20, that is, t1=2 hours after 11:20.
Distance S1 between B and C:
.
Average speed: (total distance)/(total time) =

I hope I explained it clear enough!
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