SOLUTION: A ship made a trip of 231 mi in 14 h. The ship traveled the first 98 mi at a constant rate before increasing its speed by 5 mph. It traveled another 133 mi at the increased speed.

Question 1040814: A ship made a trip of 231 mi in 14 h. The ship traveled the first 98 mi at a constant rate before increasing its speed by 5 mph. It traveled another 133 mi at the increased speed. Find the rate of the ship for the first 98 mi.
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39629)   (Show Source): You can put this solution on YOUR website!

RATE TIME DISTANCE First Part r 98 Second Part r+5 133 TOTALS 14 231

Answer by ikleyn(52875)   (Show Source): You can put this solution on YOUR website!
.
A ship made a trip of 231 mi in 14 h. The ship traveled the first 98 mi at a constant rate before increasing its speed
by 5 mph. It traveled another 133 mi at the increased speed. Find the rate of the ship for the first 98 mi.
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Your equation is = . The first addend in the left side is the time spent to cover 98 miles. The second addend is the time spent to cover 133 miles. Here "u" is he ship's rate for the first 98 mi, which is under the question. To solve it, multiply both sides by u*(u+5). You will get this quadratic equation: 98*(u+5) + 133u = 14u*(u+5). Simplify and solve it for "u". Can you complete it on your own? (I don't want to deprive you a pleasure to do it yourself :=). If not, then send a message to me through the "thank you" message form. In this case do not forget to include the ID number of the problem (1040814) into your message, in order for I could identify it.

Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

A ship made a trip of 231 mi in 14 h. The ship traveled the first 98 mi at a constant rate before increasing its speed by 5 mph. It traveled another 133 mi at the increased speed. Find the rate of the ship for the first 98 mi.

Speed =
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