SOLUTION: For a 200km journey if a van had increased its speed by 10 km/h, the journey would have been completed in 1 hour less. What was the original speed of the Van for the journey?

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Question 1037742: For a 200km journey if a van had increased its speed by 10 km/h, the journey would have been completed in 1 hour less. What was the original speed of the Van for the journey?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Travel Rates Rule is RT=D to relate RATE, TIME, DISTANCE. 

                 RATE       TIME       DISTANCE
AS DONE          r           t           200
IF               r+10       t-1          200


The exercise is similar to another one and the method would be the same.
See this as an instructive example: https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1037668.html
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
For a 200 km journey if a van had increased its speed by 10 km/h, the journey would have been completed in 1 hour less.
What was the original speed of the Van for the journey?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Let "v" be the original speed (in ) which is under the question.
In this problem, you are given the difference of times.
So, your equation should be based on this difference of times.

One time is   = , which is greater.
Another time is   = ; it is shorter.
Their difference    is 1 hour. Hence, the equation is 

 = 1.

To solve it, first multiply both sides by v*(v+10) to rid of the denominators.
Then collect like terms and simplify.
You will get a quadratic equation. Solve it by any appropriate method
(factorization or the the quadratic formula).

Please complete it on your own.


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