SOLUTION: Chad drove three times as fast Katy could Pedal. Chad drove 90 miles in 2 hours less than it took Katy to pedal 40 miles. How fast could each of them travel? How long did they tra

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Question 1037625: Chad drove three times as fast Katy could Pedal. Chad drove 90 miles in 2 hours less than it took Katy to pedal 40 miles.
How fast could each of them travel? How long did they travel?
Seriously, thank you guys!
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39621)   (Show Source): You can put this solution on YOUR website!
Basic travel rates rule for R rate, T time, D distance, is RT=D.
            RATE       TIME     DISTANCE
Chad        3r         t-2       90
Katy         r          t        40

Form the system of equations and solve it.
Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.
Chad drove three times as fast Katy could Pedal. Chad drove 90 miles in 2 hours less than it took Katy to pedal 40 miles.
How fast could each of them travel? How long did they travel?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The equation is

= .

Solve by multiplying both sides by 2.

It is easy.


Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

Chad drove three times as fast Katy could Pedal. Chad drove 90 miles in 2 hours less than it took Katy to pedal 40 miles.
How fast could each of them travel? How long did they travel?
Seriously, thank you guys!
Let Katy’s speed be S

Then Chad’s is 3S

Time Katy took to pedal 40 miles: 

Time Chad took to drive 90 miles: , or 

Since Chad took 2 hours less than Katy, then we can say that: 





2S = 10 ------ Cross-multiplying

S, or Katy’s speed = , or 

Chad’s speed: 3(5), or 



Time Katy took: , or 

Time Chad took: , or  

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