SOLUTION: Here's my question: Pearly and Peggy Sue left their dorm room at the same time and headed in opposite directions. After 9 hours, they were 1,080 miles apart. If Pearly drove 20m

Question 1036105: Here's my question:
Pearly and Peggy Sue left their dorm room at the same time and headed in opposite directions. After 9 hours, they were 1,080 miles apart. If Pearly drove 20mph faster than Peggy Sue, how fast did Peggy Sue drive?
I think the formula is Is this right? If not, how do I do it?
Found 2 solutions by jorel555, MathTherapy:
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let Peggy Sue's speed be n; then:
9n+9(n+20)=1080
9n+9n+180=1080
18n=900
n=50 mph
n+20=70 mph!!!!!!!!!!!!!!!
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Here's my question:
Pearly and Peggy Sue left their dorm room at the same time and headed in opposite directions. After 9 hours, they were 1,080 miles apart. If Pearly drove 20mph faster than Peggy Sue, how fast did Peggy Sue drive?
I think the formula is Is this right? If not, how do I do it?

How did you get 9x? Isn't that the DISTANCE (times * speed) traveled by Peggy in 9 hours?
How did I get 9(x + 20)? Isn't that the DISTANCE (times * speed) traveled by Pearly in 9 hours?
When you add these 2 distances (Peggy's and Pearly's), what should they total? Shouldn't the 2 distances sum to the distance they are apart? Of course!!
Therefore, you should get: , instead of 9x + (9x + 20) = 1
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