SOLUTION: To get to work Sam jogs 3 kilometers to the train, then rides the remaining 5 kilometers. If the train goes 40 km per hour faster than Sam's constant rate of jogging and the enti

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Question 103605This question is from textbook Precalculus
: To get to work Sam jogs 3 kilometers to the train, then rides the remaining 5 kilometers. If the train goes 40 km per hour faster than Sam's constant rate of jogging and the entire trip takes 1/2 hour how fast does Sam jog? This question is from textbook Precalculus

Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
To get to work Sam jogs 3 kilometers to the train, then rides the remaining 5 kilometers. If the train goes 40 km per hour faster than Sam's constant rate of jogging and the entire trip takes 1/2 hour how fast does Sam jog?
:
Let s = his jogging speed
then
(s+40) = train speed
:
Write a time equation: Time = Distance/speed
:
jog time + train time = .5 hrs
+ = .5
:
Multiply equation by s(s+40) and you have:
3(s+40) + 5s = .5(s(s+40))
:
3s + 120 + 5s = .5s^2 + 20s
:
8s + 120 = .5s^2 + 20s
:
0 = .5s^2 + 20s - 8s - 120
:
.5s^2 + 12s - 120 = 0; a quadratic equation
:
Use the quadratic formula to find s: a=.5; b=12; c=-120

:

:

:

:

:
s = -12 + 19.5959; we only need the positive solution here
:
s = +7.5959 km/hr is his jogging speed
:
:
Check solution by finding the time
+ =
.394 + .105 = .499 ~ .5 hrs
:
Did this make sense to you? Any questions?

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