SOLUTION: Hi, Every day Rachel walks 20 km at a certain speed. One day Rachel left 30 minutes late so she increased her speed by 25 kmh and as a result reached her destination 20 minutes ea

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Question 1035107: Hi,
Every day Rachel walks 20 km at a certain speed. One day Rachel left 30 minutes late so she increased her speed by 25 kmh and as a result reached her destination 20 minutes early. How long does she generally take to walk?
Thanks!

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39615)   (Show Source): You can put this solution on YOUR website!
Twenty minutes is .
  
            RATE     TIME          DISTANCE

NORMAL        r        t             20

ONEDAY      r+25             20

Tricky part may be examining an expression for travel time on ONE DAY.
She left half hour later and arrival was one-third of hour early.




Simplify the ONE DAY equation first.
Multiply left and right by 6.




Use the NORMAL DAY equation to substitute for rt.



divide sides by 5.


Now you have a simpler system of equations:

and this should give you a quadratic equation to solve for either variable; and use it to find the other variable.

Answer by MathTherapy(10549)   (Show Source): You can put this solution on YOUR website!

Hi,
Every day Rachel walks 20 km at a certain speed. One day Rachel left 30 minutes late so she increased her speed by 25 kmh and as a result reached her destination 20 minutes early. How long does she generally take to walk?
Thanks!
With T being normal walk-time, time taken on that day: , leading to the following SPEED equation: . 
Solving for T gives a normal walk-time of:
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