Try to draw a picture and form a data table.
rate time distance moved
BUS 80 t d 80t=d
CAR 80 t d 80t=d
t is used for both because this is the same time quantity.
Bus distance from the town becomes 80t+13.
Car distance from the town becomes 80t.
Review all of this a few times with concentration so you understand.
.
..
...
When that makes sense, look at the question.
How much time t for the bus to be twice the car, FROM THE TOWN?
Again, review all of this including this equation so that it also makes sense for you.
You want to solve for t, in this last equation.
------this is fraction of an hour, so you can convert to minutes if you want.