SOLUTION: Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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Question 103360: Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Martina leaves home at 9 a.m., bicycling at a rate of 24 mi/h. Two hours later, John leaves, driving at the rate of 48 mi/h. At what time will John catch up with Martina?
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Martina DATA:
Rate = 24 mph ; Distance = x miles ; Time = d/r = x/24 hrs
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John DATA:
Rate = 48 mph ; Distance = x miles ; Time = d/r = x/48 hrs
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EQUATION:
Martina time = John time - 2 hrs
x/24 = x/48 -2
Multiply thru by 48 to get:
2x = x - 96
x = 96 miles
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Martina time = 96/24 = 4 hrs
9:00 + 4 hrs = 1:00 PM
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John will catch up to Martica at 1:00 PM
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Cheers,
Stan H.
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