SOLUTION: a rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. the rate of the current was 4 miles per h

Question 1033560: a rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. the rate of the current was 4 miles per hour. find the rate of the rowing team in still water
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. the rate of the current was 4 miles per hour. find the rate of the rowing team in still water
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With-current DATA:
dist = 90 miles ; rate = b+4 mph ; time = d/r = 90/(b+4) hrs
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Against DATA:
dist = 10 miles ; rate = b-4 mph ; time = 10/(b-4) hrs
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Equation:
time = time
90/(b+4) = 10/(b-4)
90b - 90*4 = 10b + 10*4
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80b = 100*4
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b = 5 mph (speed of the boat in still water)
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Cheers,
Stan H.
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