SOLUTION: A woman can bicycle 46 miles in the same time as it takes her to walk 6 miles. She can ride 10 mph faster than she can walk. How fast can she walk?

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Question 1033236: A woman can bicycle 46 miles in the same time as it takes her to walk 6 miles. She can ride 10 mph faster than she can walk. How fast can she walk?
Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39613)   (Show Source): You can put this solution on YOUR website!
The description seems in general to be familiar.
            RATE        TIME      DISTANCE


BICYCLE       r+10        t         46


WALK          r           t          6

Lookup Question number 1032831.
https://www.algebra.com/algebra/homework/word/travel/Travel_Word_Problems.faq.question.1032831.html

That one only showed a data table and no further steps, as is being done here too. Can you form the necessary equations and solve the system?
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = her speed walking in mi/hr
= her speed riding in mi/hr
Let = her time in hrs for both
walking and riding
-----------------------------------
Equation for riding bicycle:
(1)
equation for walking:
(2)
-----------------------
(2)
Plug this result into (1)
(1)
(1)
(1)
(1)
She walks 1.5 mi/hr
---------------------
check:
(2)
(2)
(2) hrs
and
(1)
(1)
(1)
(1)
(1) hrs
OK
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