SOLUTION: Deandre's boat has a top speed of 10 miles per hour in still water. While traveling on a river at top speed, he went 16 miles upstream in the same amount of time he went

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Question 1033073: Deandre's boat has a top speed of
10
miles per hour in still water. While traveling on a river at top speed, he went
16
miles upstream in the same amount of time he went
24
miles downstream. Find the rate of the river current.
Found 3 solutions by addingup, josmiceli, MathTherapy:
Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
D= r*t
16(10-x)= 24(10+x)
160-16x = 240+24x
-80 = 40x
-2 = x The speed of the water is 2mph
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = the speed of the current in mi/hr
= boat's speed going downstream in mi/hr
= boat's speed going upstream in mi/hr
Let = time in hrs for both trips
--------------------------------
Equation for going downstream:
(1)
Equation for going upstream:
(2)
----------------------------
(1)
and
(2)
(2)
(2)
(2)
(2)
The rate of the current is 2 mi/hr
--------------
check:
(1)
(1)
(1) hrs
and
(2)
(2)
(2) hrs
OK
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Deandre's boat has a top speed of
10
miles per hour in still water. While traveling on a river at top speed, he went
16
miles upstream in the same amount of time he went
24
miles downstream. Find the rate of the river current.
Let me say that the speed of the current could NEVER be 

Let speed of current be C

Time taken to go upstream: 

Time taken to go downstream: 

We then get: 

24(10 - C) = 16(10 + C) ------- Cross-multiplying

240 - 24C = 160 + 16C

- 24C - 16C = 160 - 240

- 40C = - 80

C, or speed of current = , or  

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