SOLUTION: Two buses leave towns 608mi apart at the same time and travel toward each other. One bus travels 12 /mih slower than the other. If they meet in 4 hours, what is the

Question 1032617: Two buses leave towns
608mi
apart at the same time and travel toward each other. One bus travels
12

/mih
slower than the other. If they meet in
4
hours, what is the rate of each bus?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Bus I x mph
Bus II x+ 12 mph
..
They are moving towards each other

So add up their speed.

combined speed = x+ 1 x 12
( 2 x + 12 )
Time = 4 hours
Distance = 608 miles
Distance = speed * time
( 2 x 12 )* 4 = 608
8.00 x + 48 = 608
8 x = 608 + -48
8 x = 560
/ 8
x= 70 mph
Bus I = 70 mph
Bus II 70 + 12 = 82 mph
m.ananth@hotmail.ca

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