SOLUTION: a car and am motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. I

Question 1030581: a car and am motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycles. find the speed of both the car and the motorcycle, in miles per hour
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
car and am motorcycle leave at noon from the same location, heading in the same direction. The average speed of the car is 30 mph slower than twice the speed of the motorcycle. In two hours, the car is 20 miles ahead of the motorcycles. find the speed of both the car and the motorcycle, in miles per hour
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cycle DATA:
rate = x mph ; time = 2 hrs ; distance = 2x miles
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car DATA:
rate = 2x-30 mph ; time = 2 hrs ; distance = 4x-60 miles
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Equation:
car dist - cycle dist = 20 miles
4x-60-2x = 20
2x = 80
x = 40 mph (cycle speed)
2x-30 = 50 mph (car speed)
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Cheers,
Stan H.
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