SOLUTION: The speed of a moving sidewalk at an airport is
66
​ft/sec. A person can walk
3838
ft forward on the moving sidewalk in the same time it takes to walk
1010
ft on
Algebra.Com
Question 1030069: The speed of a moving sidewalk at an airport is
66
ft/sec. A person can walk
3838
ft forward on the moving sidewalk in the same time it takes to walk
1010
ft on a nonmoving sidewalk in the opposite direction. At what rate would a person walk on a nonmoving sidewalk?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The speed of a moving sidewalk at an airport is 66ft/sec.
A person can walk 3838 ft forward on the moving sidewalk in the same time it takes to walk 1010 ft on a nonmoving sidewalk in the opposite direction.
At what rate would a person walk on a nonmoving sidewalk?
:
let r = his rate walking on a non-moving sidewalk
then
(r+66) = his rate forward on moving sidewalk
:
write a time equation; time = dist/speed
=
Cross multiply
3838r = 1010(r+66)
3838r = 1010r + 66660
3838r - 1010r = 66660
r = 66660/2828
r = 23.57 ft/sec
:
:
Check this, find the actual time of each scenario
= 42.85 sec
= 42.85 sec
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