SOLUTION: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the sta

Question 1026951: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 5.5 hr and the car traveled 38.8 mph faster than the bicycle, find the average rate of each
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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The combined rates of the car and bicycle is 352 mi/5.5 hr=64 mi/hr
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B=rate of bicycle; C=rate of car=B+38.8 mph
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B+C=64 mph
B+(B+38.8mph)=64 mph
2B+38.8 mph=64 mph
2B=25.2 mph
B=12.6 mph
ANSWER 1: Average rate of bicycle was 12.6 mph.
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C=B+38.8 mph=12.6 mph+38.8 mph=51.4 mph
ANSWER 2: Average rate of car was 51.4 mph.
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CHECK:
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(Rate of car)(5.5hrs)+(rate of bicycle)(5.5hrs)=352 miles
(51.4 mph)(5.5 hrs)+(12.6 mph)(5.5 hrs)=352 miles
282.7 miles + 69.3 miles = 352 miles
352 miles = 352 miles
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SOLUTION: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the&#8203; state, at the same time that a car traveling toward it leaves the eastern end of the sta

SOLUTION: Suppose that a cyclist began a 352 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the sta