SOLUTION: Miguel walked 10 km into the country. He returned walking 3 km/h slower. The total time for the round trip was 7 h. How fast did he walk on each part of the trip?

Question 1026000: Miguel walked 10 km into the country. He returned walking 3 km/h slower. The total time for the round trip was 7 h. How fast did he walk on each part of the trip?
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Miguel walked 10 km into the country. He returned walking 3 km/h slower. The total time for the round trip was 7 h. How fast did he walk on each part of the trip?
---------
r = rate going
---
10/r + 10/(r-3) = 7
Solve for r
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = his speed walking into country in km/hr
Let = his time walking into country in hrs
= his speed returning in km/hr
= his time returning in hrs
------------------------------------
His equation for walking into country:
(1)
His equation for returning from country
(2)
-----------------------------------
(1)
(2)
(2)
Substitute (1) into (2)
(2)
(2)
(2)
(2)
use the quadratic formula

and

----------------
I can't subtract from ,
so must be the answer

---------------
his speed walking into country was 5 km/hr
his speed returning was 2 km/hr
----------------
check:
(1)
(1)
(1)
and
(2)
(2)
(2)
(2)
(2)
OK
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