SOLUTION: the average speed of the local train is 10 miles per hour less than two-thirds the speed of the express train. the local train leaves at noon. the express train leaves at 1:00 pm,
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Question 1020503: the average speed of the local train is 10 miles per hour less than two-thirds the speed of the express train. the local train leaves at noon. the express train leaves at 1:00 pm, from the same station and travels in the same direction as the local train on a parallel track. if the express train overtakes the local train at 2:00 pm, what is the speed of each train?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the speed in mi/hr of the express train
= the speed of the local train
-------------
From noon to 1 PM is 1 hr. How much of a headstart
in miles does the local train have?
----------------
----------------
Time both trains starting at 1 PM to 2 PM
Let = the distance in miles the express train travels
----------------
Equation for local train:
(1)
Equation for express train:
(2)
----------------
(1)
(1)
Substitute (2) into (1)
(1)
Multiply both sides by
(1)
(1)
(1)
(1)
(1)
----------------------
The local train's speed is 30 mi/hr
The express train's speed is 60 mi/hr
--------------------------------
check:
--------------
(1)
(1)
and
(2)
(2)
OK
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