SOLUTION: At 2:00 p.m. two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other, how fast does each car go if they meet at 5:00 p.m

Question 1015974: At 2:00 p.m. two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other, how fast does each car go if they meet at 5:00 p.m.?
If 3x represents the distance that the slower car traveled, then which expression represents the distance the faster car traveled?
A) 3(240)
B) 3x + 10
or
C) 3x + 30

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
Travel time is 3 hours.
Distance is 240 miles.
Combined speed = 240 miles/3 hours = 80 mi/hr
.
S=speed of slower car; F=speed of faster car=S+10mph
.
F+S=80mph
(S+10mph)+S=80moh
2S=70mph
S=35mph
.
ANSWER 1: Speed of the slower car is 35 mph.
.
F = S + 10 mph = 35 mph + 10 mph = 45 mph
.
ANSWER 2: Speed of the faster car is 45 mph.
.
CHECK:
(3hrs)F+(3hrs)S=240 mi
(3hrs)(45mph)+(3hrs)(35mph)=240mi
135mi+105mi=240mi
240mi=240mi

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