SOLUTION: A "Local" train leaves a station and runs at an average rate of 35 mph. An hour and a half later an "Express" train leaves the station and travels at an average rate of 56 mph on a

Question 1015965: A "Local" train leaves a station and runs at an average rate of 35 mph. An hour and a half later an "Express" train leaves the station and travels at an average rate of 56 mph on a parallel track. How many hours after the Express train starts will the it overtake the Local? (in hours)
Found 2 solutions by macston, ikleyn:
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
Local: (35mph)(1.5hr)=52.5 mi
.
When the express train starts, the local is 52.5 miles ahead.
.
The express catches up (56mph-35mph=) 21 miles per hour.
.
52.5 miles/ 21 mi/hr=2.5 hours
.
ANSWER: The express train will catch the local 2.5 hours after
the express train starts.
.

Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.
A "Local" train leaves a station and runs at an average rate of 35 mph. An hour and a half later an "Express" train leaves the station and travels at an average rate of 56 mph on a parallel track. How many hours after the Express train starts will the it overtake the Local? (in hours)
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See the lesson Travel and Distance problems in this site, Problem 2.

This problem is very similar to your.

Consider it as a sample. Read it attentively.

Then solve your problem by substituting your data.

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