Usual r t 100 New Limit r-10 t+1/2 100
Let usual speed limit be S
Then time taken at usual speed =
Decreasing the speed makes the new speed, S – 10
Time taken at new speed:
We then get:
100(2)(S – 10) = 100(2S) – S(S – 10) ------- Multiplying by LCD, 2S(S – 10)
(S - 50)(S + 40) = 0
S, or original speed limit =