Two arrangements of travel are described. The individual time quantities are not given but overall time quantities are given. Descriptions of rates are not given. Let d be the trip's distance.
Arrangement A
rate time distance
TRAIN R 60
CAR r d-60
Total 4
Arrangement B
rate time distance
TRAIN R 100
CAR r d-100
Total 4&1/6
Fill the missing time slots according to y=mx, x=y/m.
Arrangement A
rate time distance
TRAIN R 60/R 60
CAR r (d-60)/r d-60
Total 4
Arrangement B
rate time distance
TRAIN R 100/R 100
CAR r (d-100)/r d-100
Total 4&1/6
Note that 10 minutes is of an hour.
You have two time-sum equations to make. The system of equations is .
Do you see ANYTHING else?
MAYBE the time difference of the two arrangements?
A few steps of work on this time difference equation gives simplified
Return now to the system of two equations with the three variables, r, R, d, and solve each of them for d; and then equate the expressions! I will not include showing those steps here, but you may get an equation consistent with
or
You have from this another system of two equations in just r and R:
.
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I did not try to solve this further.