SOLUTION: One number is 3 less than a second number. Twice the second number is 12 more than 3 times the first. Find the two numbers.
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Question 1010644: One number is 3 less than a second number. Twice the second number is 12 more than 3 times the first. Find the two numbers.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the two numbers, x and y. Then we have
x = y - 3 ad
2y = 12 + 3x
Now substitute the first into the second equation and we get
2y = 12 + 3(y - 3)
2y = 12 + 3y - 9
2y = 3y + 3
-y = 3
y = -3
x = -3 - 3 = -6
(-6, -3)
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