SOLUTION: Initial height = h0, initial velocity =v0, a rock is thrown straight up after t seconds h= -4.9t2+v0*t+hO 0. What is the expression for time when the Rock is reached to maximum he

Question 1010334: Initial height = h0, initial velocity =v0, a rock is thrown straight up after t seconds h= -4.9t2+v0*t+hO
0. What is the expression for time when the Rock is reached to maximum height
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Given some upward initial velocity v0, we know it will slow down under the influence of gravity, until it becomes zero, or
v0 - gt = 0
t = v0/g = v0/9.8
This can also be done using calculus, but I'm not sure you're there yet...
RELATED QUESTIONS
In physics, one learns that the height of an object thrown upward from an initial height... (answered by Boreal)

If an object is given an initial velocity of v0 feet per second from a height of S0 feet, (answered by ankor@dixie-net.com)

If an object is given an initial velocity of v0 feet per second from a height of S0 feet, (answered by stanbon)

If an object is given an initial velocity of v0 feet per second from a height of S0 feet, (answered by vleith)

The path of a falling object is given by the function s=-16t2+v0t+s0 where v0 represents... (answered by scott8148)

The path of a falling object is given by the function s=-16t2+v0t+s0 where v0 represents... (answered by solver91311)

Could you please help solve for this problem it has 4 parts? I don't know where to... (answered by stanbon,solver91311)

The path of a falling object is given by the function s= -16t^2 +v0t +s0 where v0... (answered by ankor@dixie-net.com)

the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the... (answered by Alan3354)