SOLUTION: The length of a rectangle is 4 in. greater than the width. The perimeter of the rectangle is 24 in. Find the dimensions of the rectangle.

Question 100967This question is from textbook Algebra I
: The length of a rectangle is 4 in. greater than the width. The perimeter of the rectangle is 24 in. Find the dimensions of the rectangle. This question is from textbook Algebra I

Answer by doukungfoo(195) (Show Source): You can put this solution on YOUR website!
perimeter of a rectangle is 2 times Length plus 2 times width
P=2L+2W
Lets set the width equal to x
Width = x
Given: length of a rectangle is 4 in. greater than the width
Express this in terms of x
Length = x + 4
Given: perimeter of the rectangle is 24 in.
Now we can use the perimeter formula to solve for x
P=2L+2W
distribute 2 over each set of ()
combine like terms
subtract 8 from both sides
divide both sides by 4

Answer: width is 4 inches
Now find length
Length = x + 4
Length = 4 + 4
Length = 8
Answer: legnth is 8 inches
Check answers
P=2L+2W
24 = 2(8) + 2(4)
24 = 16 + 8
24 = 24

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