SOLUTION: A cyclist bikes at a constant speed for 25 miles. He then returns home at the same speed but takes a different route. His return trip takes 1 hour longer and is 30 miles. Find h

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Question 1007801: A cyclist bikes at a constant speed for 25 miles. He then returns home at the same speed but takes a different route. His return trip takes 1 hour longer and is 30 miles. Find his speed?
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!
where is distance, is speed, and is time
if a cyclist bikes at a constant speed for , we have
..............solve for
.......eq.1
if he then returns home at the same speed but takes a different route, and his return trip takes longer and is , we have
.............solve for
.........eq.2
eq.1 and eq.2 have equal left sides, so make equal right sides and solve for
.......cross multiply




hours
now find
.......eq.1

=> speed
and
.........eq.2


=> speed on his return trip
so, in both directions his speed was constant and it was

Answer by MathTherapy(10549)   (Show Source): You can put this solution on YOUR website!
A cyclist bikes at a constant speed for 25 miles. He then returns home at the same speed but takes a different route. His return trip takes 1 hour longer and is 30 miles. Find his speed?
Let speed be S
Then time on outbound trip =
Time taken on return trip =
Time equation formed:
25 = 30 – S ------- Multiplying by LCD, S
S, or speed = 30 – 25, or mph
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