Question 1006821: A high school student in Seattle, Washington, attends the University of Central Florida. On the way to UCF he took a southern route. After graduation he returned to Seattle via a northern trip. On both trips he had the same average speed. If the southern trek took 45 hours, the northern trek took 50 hours, the northern trek was 295 miles longer, how long was each trip?
Answer by macston(5194)   (Show Source):
You can put this solution on YOUR website! .
To travel 295 extra miles took 5 hours, so his
(constant) speed was 295 miles/5 hours=59 mph.
The southern trip was:
45 hrs x 59 mph = 2655 miles
.
The northern trip was:
50 hrs x 59 mph = 2950 miles
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