a plane traveled 580 miles to zambaouga and back. the trip there was with the wind. it took 5 hours. the trip back was against the wind. the trip back was 10 hours. find the speed of the plane in still air and the speed of the wind
Let speed of plane in still air be S, and wind speed, W
With total speed with wind being 116 () mph, we get:
S + W = 116 ------- eq (i)
With total speed against wind being 58 () mph, we get:
S - W = 58 -------- eq (ii)
2S = 174 -------- Adding eqs (i) & (ii)
S, or speed of plane in still air = , or mph