SOLUTION: Find three consecutive positive odd numbers such that the sum of the square of the two smaller numbers is 33 more than the square of the largest number.

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Question 998784: Find three consecutive positive odd numbers such that the sum of the square of the two smaller numbers is 33 more than the square of the largest number.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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N=smallest integer, N+2=middle integer, N+4=largest integer
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N%5E2%2B%28N%2B2%29%5E2=%28N%2B4%29%5E2%2B33
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N%5E2-4N-45=0
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%28N-9%29%28N%2B5%29=0
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N-9=0 OR N%2B5=0
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N=9 OR N=-5
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ANSWER: 9 is the only positive result.
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CHECK:
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9%5E2%2B%289%2B2%29%5E2=%289%2B4%29%5E2%2B33
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81%2B121=169%2B33
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202=202
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