SOLUTION: One number is four more than the other. The square of the smaller number increased by three times the larger is 66. Find the two numbers.

Question 996731: One number is four more than the other. The square of the smaller number increased by three times the larger is 66. Find the two numbers.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
One number is four more than the other. The square of the smaller number increased by three times the larger is 66. Find the two numbers.
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Equations:
x = y + 4
Note:: That means "y" is the smaller number
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y^2 + 3x = 66
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Substitute for "x" and solve for "y"::
y^2 + 3(y+4) - 66 = 0
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y^2 + 3y - 54 = 0
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(y-6)(y+9) = 0
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y = 6 or y = -9
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If y = 6, x = y+4 = 10
If y = -9, x = y+4 = -5
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Cheers,
Stan H.
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