SOLUTION: I really need some help with this problem, if anyone's not busy I would appreciate any help at all. �a waitress sold 17 ribeye steak dinners and 20 grilled salmon dinners, total

Question 994723: I really need some help with this problem, if anyone's not busy I would appreciate any help at all.
�a waitress sold 17 ribeye steak dinners and 20 grilled salmon dinners, totalling $590.81 on a particular day. Another day she sold 24 ribeye steak dinners and 10 grilled salmon dinners, totaling $580.66. How much did each type of dinner cost?
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
a waitress sold 17 ribeye steak dinners and 20 grilled salmon dinners, totalling $590.81 on a particular day. Another day she sold 24 ribeye steak dinners and 10 grilled salmon dinners, totaling $580.66. How much did each type of dinner cost?
------------
17r + 20s = 59081
24r + 10s = 58066 x2 --> 48r + 20s = 116132
----
17r + 20s = 59081
48r + 20s = 116132
-------------------------- Subtract
-31r = -57051
r = 1840.355 --> $18.40
Can you solve for s?

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
let ribeye steak dinners be and grilled salmon dinners
if a waitress sold ribeye steak dinners and grilled salmon dinners, totaling $ on a particular day, then we have
.........eq.1
if another day she sold ribeye steak dinners and grilled salmon dinners, totaling $, then we have
.........eq.2
solve the system:
.........eq.1
.........eq.2...=> both sides multiply by
-------------------------------------------
.........eq.1
.........eq.2=> subtract eq.1 from eq.2
-----------------------------------------------------

now find
.........eq.2

How much did each type of dinner cost?
ribeye steak dinners cost and
grilled salmon dinners cost

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