SOLUTION: a waitress sold 17 ribeye steak dinners and 20 grilled salmon dinners, totalling $590.81 on a particular day. Another day she sold 24 ribeye steak dinners and 10 grilled salmon di
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Question 994720: a waitress sold 17 ribeye steak dinners and 20 grilled salmon dinners, totalling $590.81 on a particular day. Another day she sold 24 ribeye steak dinners and 10 grilled salmon dinners, totaling $580.66. How much did each type of dinner cost?
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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R=cost of rib-eye dinner; S=cost of salmon dinner
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24R+10S=$580.66
10S=$580.66-24R
20S=$1161.32-48R Use this to substitute for 20S below
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17R+20S=$590.81 . Substitute for 20S.
17R+($1161.32-48R)=$590.81
-31R=-$570.51
R=$18.40
ANSWER 1: Rib-eye dinner costs $18.40.
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24R+10S=$580.66
24($18.40)+10S=$580.66
$441.60+10S=$580.66 441.69
10S=$139.06
S=$13.91
ANSWER 2: A salmon dinner costs $13.91.
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CHECK:
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17R+20S=$590.81
17($18.40)+20($13.91)=$590.81
$312.80+$278.20=$590.81
$591=$590.81
19 cent discrepancy from rounding to nearest cent.
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