SOLUTION: The sum of two numbers is 82. The larger exceeds the smaller by 16. Find the numbers.
Algebra.Com
Question 992996: The sum of two numbers is 82. The larger exceeds the smaller by 16. Find the numbers.
Answer by ikleyn(52835) (Show Source): You can put this solution on YOUR website!
.
= = 33 - this is the smaller number.
33 + 16 = 49 - it is the larger number.
Check: 33 + 49 = 82.
RELATED QUESTIONS
The sum of two numbers is 43. Twice the larger number exceeds three times the smaller... (answered by eperette)
the larger of two numbers is seven times the smaller. if the sum of the two numbers... (answered by solver91311)
the sum of two numbers is 85. Two times the smaller number exceeds the larger number... (answered by rothauserc)
The sum of two numbers is 50. The larger exceeds the smaller by 22. What is the larger... (answered by JulietG)
the sum of two numbers is 50. two times the smaller number exceeds the larger number by... (answered by Fombitz)
the sum of two numbers is 50. Two times the smaller number exceeds the larger number by... (answered by godsgirls)
the sum of two numbers is 50. two times the smaller number exceeds the larger number by... (answered by josgarithmetic)
The sum of two numbers is 50. Two times the smaller number exceeds the larger number by... (answered by stanbon)
The sum of the reciprocals of two numbers is 7. The larger reciprocal exceeds the smaller (answered by ikleyn,math_tutor2020)