SOLUTION: Find three numbers such that the second number is 3 more than twice the first number,and the third number is four times the first number. The sum of the three numbers is 164

Question 992786: Find three numbers such that the second number is 3 more than twice the first number,and the third number is four times the first number. The sum of the three numbers is 164
Found 2 solutions by stanbon, Cromlix:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find three numbers such that the second number is 3 more than twice the first number,and the third number is four times the first number. The sum of the three numbers is 164.
1st:: x
2nd:: 2x+3
3rd:: 4x
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Equation:
x + 2x+3 + 4x = 164
7x = 161
----
x = 23 (1st)
2x+3 = 49 (2nd)
4x = 92 (3rd)
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Cheers,
Stan H.
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Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Make first number = 'x'
Second number = 3 + 2x
Third number = 4x
Total = 164
So,
x + (3 + 2x) + 4x = 164
x + 3 + 2x + 4x = 164
Collect like terms:
x + 2x + 4x = 164 - 3
7x = 161
x = 23
First number = 23
Second number = 49
Third number = 92
Hope this helps :-)
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