SOLUTION: the sum of two numbers is 71. if three times the smaller number is subtracted from the larger number, the result is 3. find the two numbers

Question 991706: the sum of two numbers is 71. if three times the smaller number is subtracted from the larger number, the result is 3. find the two numbers
Found 3 solutions by stanbon, addingup, MathTherapy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
the sum of two numbers is 71. if three times the smaller number is subtracted from the larger number, the result is 3. find the two numbers
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Equations:
x + y = 71
x - 3y = 3
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Subtract and solve for "y"::
4y = 68
y = 17
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Solve for "x"::
x + 17 = 71
x = 54
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Cheers,
Stan H.
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Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
a+b=71, therefore a=71-b
b-3a=3
b-3(71-b)=3
b-213-3b= 3
-2b= -210
b= -210/-2
b= 105 Now go back to the original formula:
a+105= 71
a= 71-105
a= -34 This is b. Let's try it in the problem. It says that the sum is 71:
105+(-34)= 71
Now the problem says, if three times the smaller number is subtracted from the larger number, the result is 3
3*34= 102; 105-102= 3
We've got the right answers.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

the sum of two numbers is 71. if three times the smaller number is subtracted from the larger number, the result is 3. find the two numbers

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