SOLUTION: Find three consecutive odd numbers such that four times the first number decreased by 28 is equal to the sum of the last two numbers.

SOLUTION: Find three consecutive odd numbers such that four times the first number decreased by 28 is equal to the sum of the last two numbers.

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Question 991532: Find three consecutive odd numbers such that four times the first number decreased by 28 is equal to the sum of the last two numbers.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
x, x+2, x+4 are the three integers
.
4x-28=(x+2)+(x+4)
4x-28=2x+6
2x=34
x=17 ANSWER 1: The first number is 17.
x+2=17+2=19 ANSWER 2: The second number is 19.
x+4=17+4=21 ANSWER 3: The third number is 21.
.
CHECK:
4(17)-28=19+21
68-28=40
40=40

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