SOLUTION: a student multiplies 3 numbers and the result is 45. one of the number is 4 and the other two numbers one is greater than the other by 6, what are the two numbers?

Question 989159: a student multiplies 3 numbers and the result is 45. one of the number is 4 and the other two numbers one is greater than the other by 6, what are the two numbers?

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
.
x=smaller number
(4)(x)(x+6)=45
4x^2+24x=45
4x^2+24x-45=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1296 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1.5, -7.5. Here's your graph:

x=1.5 or -7.5
.
For x=1.5, x+6=7.5 : For x=-7.5, x+6=-1.5
ANSWER: The other two numbers are 1.5 and 7.5 or -1.5 and -7.5.
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