SOLUTION: Find 3 consecutive integers such that thrice the first plus twice the second is 16 less than the third number.

Question 989104: Find 3 consecutive integers such that thrice the first plus twice the second is 16 less than the third number.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
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F=first integer; S=second integer=F+1; T=third integer=F+2
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3F+2S=T-16
3F+2(F+1)=(F+2)-16
3F+2F+2=F-14
5F+2=F-14
4F=-16
F=-4 ANSWER 1: The first integer is -4.
S=F+1=-4+1=-3 ANSWER 2: The second integer is -3.
T=F+2=-4+2=-2 ANSWER 3: The third integer is -2.
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CHECK:
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3F+2S=T-16
3(-4)+2(-3)=(-2)-16
(-12)+(-6)=-18
-18=-18

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