SOLUTION: The tens digit of a two-digit number exceeds twice its units digit by 1. If the digits are reversed, the number is four more than three times the sum of the digits. Find the origin

Question 985062: The tens digit of a two-digit number exceeds twice its units digit by 1. If the digits are reversed, the number is four more than three times the sum of the digits. Find the original number.
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Let the number be in the form AB, where is theg10s digit and B is the ones digit.
Sometimes the quickest way to solve a problem is to brute force the possible answers. I think thhat is the case here.
You are told
that says the units digit cannot be more than 4.
The only options are
B =9 when A=4
B = 7 when A=3
B = 5 when A=2
B=3 when A=1
B=1 when A=0
So the only possible answers are 94, 73, 52, 31 and 10
Use these 5 options and to find which one satisfies "If the digits are reversed, the number is four more than three times the sum of the digits"
SO reversing the digits say our 5 numbers become 49, 37, 25, 13 and 1.
The only one that works is 25. (which is 3*7 + 4
So the number is 52

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