SOLUTION: a number consists of three digit whose sum is 17 . The middle digit is one more than the sum of the other two digits. If digits are reversed, the new number is 396 less than the or
Algebra.Com
Question 976910: a number consists of three digit whose sum is 17 . The middle digit is one more than the sum of the other two digits. If digits are reversed, the new number is 396 less than the original number. What is the number?
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a+b+c=17
b=1+a+c
100a+10b+c-100c-10b-a=396
99a-99c=396
a-c=4
a=c+4
b=1+a+c
b=1+c+4+c
b=5+2c
a+b+c=17
(c+4)+[5+2c]+c=17
4c+9=17
4c=8
c=2
a=6
b=9
number is 692
check
692-296=396
ok
RELATED QUESTIONS
The sum of the digits of a three digit number is 17. The middle digit is two more than... (answered by ankor@dixie-net.com)
The sum of the digits of a three digit number is 17. The middle digit is two more than... (answered by mananth)
A number consist of three digits of whose sum is 17 the middle digit exceeds the sum of... (answered by ankor@dixie-net.com,MathTherapy)
The sum of the digits of a three -digit number is 17. The ones degit is two more than the (answered by Edwin McCravy,ptaylor)
A three digit number is equal to 17 times the sum of its digit
If 198 is added to the... (answered by Alan3354)
A three digit number is equal to 17 times the sum of its digit
If 198 is added to the... (answered by stanbon)
The tens digit of a two-digit number is 1 more than three times the units digit. If the... (answered by math_helper)
A number consist of 3 digits whose sum is 14, the middle digit is equal to the number of... (answered by josgarithmetic,ankor@dixie-net.com,greenestamps)
Find a three digit number whose third digit is one less than the second digit. The sum of (answered by richwmiller)