SOLUTION: the sum of a two digit number and obtained by reversing the order of its digit is 99.if the digit differ by 3.find the number.
Algebra.Com
Question 975129: the sum of a two digit number and obtained by reversing the order of its digit is 99.if the digit differ by 3.find the number.
Answer by ibworldacademy(1) (Show Source): You can put this solution on YOUR website!
10x+y+10y+x= 99
11x+11y=99
x+y=9
x-y=3
solving simultaneously
x=6, y=3
IB World Academy
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