SOLUTION: find a real number that exceeds its cube by 2.
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Question 97253
This question is from textbook
:
find a real number that exceeds its cube by 2.
This question is from textbook
Found 2 solutions by
Nate, edjones
:
Answer by
Nate(3500)
(
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):
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put this solution on YOUR website!
x = x^3 + 2
Obviously, the number is negative.
Between -2 and -1 ...
About -1.52
Answer by
edjones(7311)
(
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):
You can
put this solution on YOUR website!
x=x^3+2
x^3-x+2=0 (no factors)
x=-1.5213797 (TI calculator)
x^3=-3.5213797
Ed